The graph of the equation

Step-by-step explanation:

This equation has a vertical asymptote at x = -2 and a horizontal asymptote at y = 1. This is stuff you should know about rational equations as you learn about them. The vertical asymptote serves as the locked gate or really high wall that the graph cannot go through nor can it go around or over or under. The graph will never cross through the VA. The horizontal asymptote is a horizontal line, y = 1, that reveals the graph's end behavior. So picture this:

We have an x/y coordinate plane. There is a vertical asymptote at x = -2 and a horizontal line at y = 1. This graph, because it cannot go through the vertical asymptote, is "split" into 2 parts, basically. The left "part" comes in along the horizontal asymptote from negative infinity, almost touching it but not quite, and when it reaches x = -2, it drops along the vertical asymptote, almost touching it but not quite and goes down into negative infinity. The right "part" of the graph comes down from positive infinity along the vertical asymptote, almost touching it but not quite, and when it reaches y = 1, it curves along that line off into positive infinity.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

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