A particle increases its speed from 8 x 105 m/s to 1.1 x 10 m/s. What
is the percentage increase?

Datos:

Vi=20m/s

Vf=30m/s

a=5m/s2

d=?

Cálculo de la distancia recorrida:

Vf^2 = Vi^2 + 2 * a * d

Reemplazando datos:

(30m/s)^2 = (20m/s)^2 + 2 * 5m/s2 * d

900m2/s2 = 400m2/s2 + 10m/s2 * d

900m2/s2 - 400m2/s2 = 10m/s2 * d

500m2/s2 = 10m/s2 * d

d = 500m2/s2 / 10m/s2

d = 50m

Step-by-step explanation:

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6