A vet wants to determine which of two brands of flea treatment is best for the cats in the shelter. Before using one of the few treatments on all the cats the vet decides to conduct experiment Individual cats. Which of the following two plans for randomly assigning the treatments should the vet use? Explain. Plan A: Choose the 16 cats that are most riddled with fleas. Apply Brand M to al 16 of those cats. Apply Brand N to the remaining 16 cats
Plan B: Choose 16 of the 32 cats at random. Apply Brand M to those 16 cats and Brand N to the remaining 16 cats
a. Plans A and B are equivalent because they both follow experimental design.
b. Plans A and B are both poorly designed because there are not entugh cats to test
c. Plan A, because the cats that have the most heas need the free treatment the most and should be treated first
d. Plan B, because the sample of cats is randomly chosen
e. The plans cannot be evaluated from the information given

step-by-step explanation:

i dont get

i have no clue at all sorry

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.