V=u+ 2at Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s?) and t is the
time (in seconds)
Find v when a is 4 m/s2, u is 3 m/s, and t is 72 seconds.

A.579 m/s
B.1728 m/s
C.436 m/s
D. 864 m/s

the answer is A 579m/s

Step-by-step explanation:

Given,

v=?    u=3m/s a=4m/s^2 and  t=72

Now,

v=u+2at

=3+2{4(72)}

= 3+2(288)

=3+576

=579m/s

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places