Evaluating Linear Piecewise Functions Try it
Consider the function:
What are these values?
+ 2x,
xs-1
f(-3) =
f(x) =
-5+
Ž +
3x – 1 < x <3
*x,
f(-1) =
x 23
f(3) =
-5 -4 -3 -2 -1
0
1
2
3
4
5

On a certain portion of an experiment, a statistical test result yielded a p-value of 0.21. what can you conclude? 2(0.21) = 0.42 < 0.5; the test is not statistically significant. if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 21% of the time, so the test is not statistically significant. 0.21 > 0.05; the test is statistically significant. if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 79% of the time, so the test is not statistically significant. p = 1 - 0.21 = 0.79 > 0.05; the test is statistically significant.