Given 7 cos θ -3 = 2;0° <θ < 180 ° Determine sin θ

Given: 5sin2(θ) - 6sin(θ) - 8 = 0 where 180 < θ < 270. Solution: Let x = sin(θ). Substituting x to the equation: -> 5sin2(θ) - 6sin(θ) - 8 = 0.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

pretty sure 750 each month!

step-by-step explanation: