1. Find the least number of terms that is required such that the geometric series 3 + 2 + 4/3 + … just exceeds 8.25. 2. The first term and common ratio of a geometric progression are a and r respectively. The geometric progression has 7 terms with the difference between the last term and the first term is 31 ½ , while the difference between the fourth term and the first term is 3 ½ . Find the sum of all the terms of the progression. ​

idk

step-by-step explanation: i just don't

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

a precentage of 6th graders. the population is all 6th graders. let me know if i'm wrong, i hope this ! : )

step-by-step explanation:

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.