find the measure of the largest interior angle of this polygon ​

122(3x-4).

Step-by-step explanation:

First, let's take a look at the polygon

The polygon has 5 sides.

We can calculate it's sum of interior angles by using (n-2)*180

Here, number of sides(n)=5

Therefore, (n-2)*180=(5-2)*180=3*180=540

Now that we got that out of the way, let's solve for x

2x+9+3x-8+3x-4+3x-10+2x+7=540

or,13x-6=540

or,13x=546

or,x=42

Now, solve for each interior angle,

2x+9=93

3x-8=118

3x-4=122

3x-10=116

2x+7=91

The largest here s 122 which is 3x-4.

SO, the largest interior angle=122(3x-4).

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.

your answer would be b

step-by-step explanation: