A can do ajob in 16 days and B can do same job in 12 days. With the help of C they did the job in 4 days only. Then, C alone can do the job in..

48 days

Step-by-step explanation:

We know that,

Number of days A requires to do piece of work =16 days

Number of days B requires to do piece of work =12 days

Let us consider number of days C requires to do piece of work =x days

Number of days A,B and C together requires to do the piece of work =6 days

∴ We can calculate, work done by A in 1 day =1/16

Work done by B in 1 day =1/12

Work done by C in 1 day =1/x

Work done by A,B and C together in a 1 day =1/6

Now, work done by A,B and C together in 1 day is also equal to the sum of work done by each of them in 1 day =1/16+1/12+1/x=7/48+1/x

Therefore,

7/48+1/x=1/6

(7x+48)/48x=1/6

42x+288=48x

6x=288

x=288/6=48

∴C can do the work in 48 days.

neither i nor ii 56 / 4.9 = 11.91489362 and 82 / (11+5) =5.125 so i is wrong

ii. (24/8+2) times 3 = 15 and (42+9)/2 =25.5

step-by-step explanation:

56

●yes, this statement is absolutely apt.

hope this you