A chocolate factory has three classifications for the candies that it makes: Caramels (12 varieties). please help!!!
Milk Chocolate (6 varieties)
Dark Chocolate (9 varieties)
1. Set up the NOTATION to figure out the different ways to choose 7 of the 12 Caramels
2. Set up the NOTATION to figure out the different ways to choose 3 of the 6 Milk Chocolates
3. Set up the NOTATION to figure out the different ways to choose 5 of the 9 Dark Chocolates
4. A customer has ordered an assortment to consist of seven types of caramels, three types of chocolate, and five types of dark chocolates.
How many such assortments are possible?

1. 792 2. 20. 3. 126. 4.1995840

Step-by-step explanation:

Use the formula C(n,r)= n!/ r/ (n-r)! where n is total quantity of varieties and r is the quantity uou should choose.

1) n=12 (total quantity); r= 7

C(12,7)= 12!/(7! *(12-7)!)= 8*9*10*11*12/ (5*4*3*2)= 8*9*11= 72*11= 792

2) n=6 r=3

C(6,3)= 6!/ (3! * (6-3)!)= 6!/ (3!)^2= 4*5*6/ 3*2= 20.

3) C(9,5)= 9!/ (5!*4!)= 6*7*8*9/ (4*3*2*1)= 2*63= 126

4) You need to choose the whole set which consists of three components that has been defined. Multiply previous results

792*20*126= 1995840.

hello,

as   long as they add up to 180 its correct.

x:       y:  

-1         4

0         4

1         6

2         18

3         20