UN TANQUE CILINDRICO DE 6 METROS DE RADIO Y 10 METROS DE ALTURA SE LLENA DE AGUA. SE ABRE UN AGUJERO EN EL FONDO DEL TANQUE Y EN ESE MOMENTO EL AGUA
SALE A RAZÓN DE 6 m3/
min
¿CON QUÉ RAPIDEZ ESTÁ CAMBIANDO LA ALTURA DEL AGUA EN EL TANQUE?

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

answer: the answer is 127 degrees

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take good notes.

do your homework.

use mnemonics and other tricks.

do practice tests.

note: the best i know.

ghjmutmum

step-by-step explanation: