An object is launched at 14.7 meters per second from an 88.2 meter tall platform. The equation for the object's height (ℎ)
(
h
)
at time
()
(
t
)
seconds after launch is
ℎ()=−4.92+14.7+88.2
h
(
t
)
=
−
4.9
t
2
+
14.7
t
+
88.2
. Assuming
=0
t
=
0
is when the object is launched and
ℎ=0
h
=
0
is when the object is level with the ground, when does the object strike the ground?

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.

6 meters

step-by-step explanation: