(i (1) Sketch the curve given by following
functions below. Find the stationary points,
the gradient and the turning points (max and
minimum values).
(3
po
(a
(a) x°- 6.rº + 9x-1
(b
(b) 4x + 15x? - 18x + 7
(c
(c) x - 3x2 + 3x + 2
(d
3x² – 2x² - 5 - 5
​

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

is there any photos or whatever?

so, converting firstly the mixed fractions to improper fractions and then "adding".