General solution of x if 2cosx=3tanx

sin

2

xsecx+

3

tanx=0

⇒

cosx

sin

2

x

+

3

tanx=0

⇒sinxtanx+

3

tanx=0

⇒tanx(sinx+

3

)=0

⇒tanx=0 or sinx+

3

=0

⇒tanx=0 or sinx



=−

3

∵rangeofsinx∈[−1,1]

∴tanx=0

∴x=nπ

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

no he doesnt because "-16' is negatiive

step-by-step explanation: