What is the value of x

The triangle is formed by using the diameter as its base, so angle opposite to the diameter, i.e., ∠QRS = 90°

Given that QR and SR are equal, so it is an isosceles triangle. Hence, ∠RQS and ∠RSQ are equal. Hence, ∠RSQ = x + 6° because given that ∠RQS = x + 6°.

We know that all angles of a triangle adds up to 180°.

So, (x+6°) + (x+6°) + 90° = 180°

=> 2(x+6°) + 90° = 180°

=> 2(x+6°) = 180° - 90°

=> 2(x+6°) = 90°

=> 2x + 12° = 90°

=> 2x = 90° - 12°

=> 2x = 78°

=> x = 78°/2

=> x = 39°

x^5/3y^1/3 the correct answer

hope it

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step-by-step explanation: