1)The sum of two consecutive multiples of 5 is55. Find these multiples. 2)The sum of three consecutive integers is 93. What are the integers?
3)If five is subtracted from three times a number, the result is 10. What is the number?

Part 1

Let the consecutive multiples be 5x and 5x + 5

ATQ

5x + 5x + 5 = 55

10x = 55 - 5

10x = 50

x = 5

Answer is 25 and 30

Part 2

Let the number be x , x + 1, x + 2

ATQ

x + x + 1 + x + 2 = 93

3x + 3 = 93

3x = 93 - 3

x = 90/3

x = 30

The integers are 30,31 and 32

Part 3

Let the number be x

ATQ

3x - 5 = 10

3x = 10 + 5

x = 15/3

x = 5

The number is 5

Answered by Gauthmath must click thanks and mark brainliest

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

9 sandwiches per hour

step-by-step explanation:

when we have a rate, we want a 1 in the denominator

27/3 = 9

27 sandwiches/ 3 hours = 9 sandwiches/hour