subject
Mathematics, 28.07.2021 18:30 my7butterflies

Tay-Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carriers of the disease, the probability that their offspring will develop the disease is approximately 0.25. Suppose that a husband and wife are both carriers and that they have four children. If the outcomes of the four pregnancies are mutually independent, what are the probabilities of the following events? a. All three children will develop Tay–Sachs disease.
b. Only one child will develop Tay–Sachs disease.
c. The third child will develop Tay–Sachs disease, given that the first two did not.

ansver
Answers: 1

Another question on Mathematics

question
Mathematics, 21.06.2019 13:30
Combined megan and kelly worked 60 hours.kelly worked twice as many hours as megan.how many hours did they each worked?
Answers: 3
question
Mathematics, 21.06.2019 19:00
Point r divides in the ratio 1 : 3. if the x-coordinate of r is -1 and the x-coordinate of p is -3, what is the x-coordinate of q? a. b. 3 c. 5 d. 6 e. -9
Answers: 1
question
Mathematics, 21.06.2019 20:10
60 2(x + 2) in the diagram, gef and hef are congruent. what is the value of x?
Answers: 2
question
Mathematics, 21.06.2019 21:00
Suppose that in 2008 , 840,800 citizens died of a certain disease assuming the population of teh country is 399 miliion, what is the mortality rate in units of deaths per 100,000 people?
Answers: 1
You know the right answer?
Tay-Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are...
Questions