The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X: What is the measure of angle ACB?

32

Step-by-step explanation:

First, one theorem states that (arc AB - arc AX) / 2 = angle ACB. We know that arc AB is 176, so we have

(176 - arc AX) /2 = ∠ACB

Next, the Inscribed Angle Theorem states that

arc AX/2 = ∠ABX

multiply both sides by 2

56 * 2 = arc AX = 112

Therefore, ∠ACB = (176-112)/2 = 64/2 = 32

sorry but i cant draw that

choice b

step-by-step explanation:

f(x) = 88x^2 -264x + 300

the line of symmetry of a parabola is defined by

h = -b/2a

where ax^2 +bx+c=0

so

h = - -264/ (2*88)

h = 3/2

so x = 1.5