A box contains 28 balls of which 7 are red, 7 are blue, 14 are green. If a ball is drawn at random, find the probability that it is neither blue nor red.

1 /4

Step-by-step explanation:

Given that :

Number of red = 7

Number of Blue = 7

Number of green = 14

Total number of balls = 28

Probability of picking a ball that is neither red nor green.

Probability = required outcome / Total possible outcomes

P(neither red nor green) = P(picking a blue ball) = 7 / 28 = 1/4

if im undersanding the question correctly, its organized from 10

step-by-step explanation: