g According to a report from a particular​ university, ​% of female undergraduates take on debt. Find the probability that of the female undergraduates have taken on debt if female undergraduates were selected at random. What probability should be​ found

P(0 female undergraduate takes on debt) ;

0.00635

Step-by-step explanation:

Probability of taking on debt, p = 0.43

q = 1 - p = 1 - 0.43 = 0.57

Number of samples, number of trials, n = 9

To obtain the probability that none of the female undergraduate take on debt :

P(0 female undergraduate takes on debt)

P(x = 0) ; using the binomial probability relation :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 0) = 9C0 * 0.43^0 * 0.57^(9-0)

P(x = 0) = 9C0 * 0.43^0 * 0.57^9

P(x = 0) = 1 * 1 * 0.006351461955384057

P(x = 0) = 0.006351461955384057

P(x = 0) = 0.00635

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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