Daniel used the formula to find the area of the following special trapezoid. His work is shown. Identify his error and correct it to find the area of the special trapezoid. \(\text{Line}\ 1:\ A=\frac{1}{2}\left(6\right)\left(7+ 7\right)\) \(\text{Line}\ 2:\ A=\frac{1}{2}\left(6\right)\left(14 \right)\) \(\text{Line}\ 3:\ A=\left(3\right)\left(7\right)\) \(\text{Line}\ 4:\ A=21\text{ cm}^2\)

Step-by-step explanation:

CSYJDKUFTIGY.,,JHFMXJZDSRUTSIDFOULVGCFK

I had the same issue.

Step-by-step explanation:

Here is the actual equation.

A=1/2(6)(7+7)

A=1/2(6)(14)

A=(3)(7)

A=21cm^2

He messed up on line 3 by multiplying 1/2 to both numbers. It should be A=(3)(14) and he would have gotten 42.

answer: a.   one is a factor of every whole number since every number is divisible by itself.

i hope this is what you were looking for.

see attached graph