What were the dimensions of the original photo? 4 inches by 4 inches 6 inches by 6 inches 10 inches by 10 inches 12 inches by 12 inches

6 inches by 6 inches

Step-by-step explanation:

Area of the square = 256 inches ²

Given equation:

(x + 10)² = 256

Where,

x = side measure of the original square

(x + 10)² = 256

(x + 10)(x + 10) = 256

x² + 10x + 10x + 100 = 256

x² + 20x + 100 = 256

x² + 20x + 100 - 256 = 0

x² + 20x - 156 = 0

Solve the quadratic equation by factorization

Find two numbers whose product is -156 and sum is 20

The numbers are -26 and 6

x² + 26x - 6x - 156 = 0

x(x + 26) - 6(x + 26) = 0

(x + 26) (x - 6) = 0

x + 26 = 0 or x - 6 = 0

x = -26 or x = 6

Side length of a square can not be negative

Therefore,

x = 6 inches

6 inches by 6 inches

2x^2+5x+17

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