On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles, find the total distance traveled in the two days.

The total distance traveled in two days would be 380 miles.

Let's see how we calculate the distance.

Given that,

Speed on first day = 40 mph

Since,

Speed = Distance/Time

∵ 40 = /   ...(i)

Speed on the second day = 60 mph

Distance traveled =   - 20

Time taken = - 2

Since,

Speed = Distance/Time

∵ 60 = ( - 20)/ ( - 2) ...(ii)

As we know,

Total distance =

=   +

= 2 - 20  ...(iii)

From (i), we can deduce that,

= 40

= /40

Now, by putting the values of and  in equation (ii), we get

60 = ( - 20)/ ( - 2)

⇒ - 20 = 60( - 2)

⇒ - 20 = 60 - 120

⇒ - 20 = 60 * (

⇒ = 3

⇒ - 3

⇒ - /2 = -100

∵ = 200

By substituting the value of in equation (iii),

Total distance = 2 - 20

= 2(200) - 20

= 400 - 20

= 380 miles

Learn more about 'speed and distance' here:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

b.-4 units

all you   do is count how many times you move