[asy] void shademe(pair A) { fill(A--(A+(1,0))--(A+(1,1))--(A+(0 ,1))--cycle, gray(0.8)); } size(90); shademe((0,1)); shademe((1,0)); for(int i=0;i<=2;i+=1){ draw((i,0)--(i,2)); draw((0,i)--(2,i)); } label("$60\%$",(0,1.5),W); label("$25\%$", (0,0.5), W); label("$33\frac{1}{3}\%$", (0.5,2),N); label("$50\%$", (1.5,2),N); [/asy]

john got lost so he didn't know what to do and it was crazy because he didn't except it

step-by-step explanation:

123123 step byt step

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.