A baseball player throws a baseball from a height of 1 m above the ground and its height is given by the equation h= -3.2^2+ 12.8t +1, where H is the height in meters above the ground, and t, in seconds, is its time in the air [see the image below]. When, to the nearest tenth of a second, will the ball hit the ground? (You must solve by factoring)!!!<<<<< it's important that you do. please solve this ASAP

4.1 sec

Step-by-step explanation:

h(t)=-3.2t^2+12.8t+1

h(t)=-3.2(t^2-4t)+1

h(t)=-3.2(t^2-4t+4-4)+1

h(t)=13.8-3.2(t-2)^2

For the ball to touch ground, h(t)=0.

13.8-3.2(t-2)^2=0

(t-2)=2.0766

t=4.07≈4.1 sec.

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step-by-step explanation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11