What is the tenth term of an arithmetic sequence with second term 100 and common difference −12?

4

Step-by-step explanation:

d = -12

a2 = 100

We know the formula for the terms of an arithmetic sequence is

an = a1+d(n-1)

We can find the first term

100 = a1-12(2-1)

100 = a1-12(1)

Add 12 to each side

112 = a1

The first term is 112

Using the formula with n=10

a10 = 112-12(10-1)

a10 = 112 -12(9)

     = 112-108

     = 4

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