The fifth term of an arithmetic progression is 5 and the sum of the first six terms is 12. Find the sum of all the terms from the seventh term to the twelfth term.​

87

Step-by-step explanation:

Let a be the first term of the A. P. and d be the common difference.

ATQ, 5a+10d=5 and 6a+15d=12, a=-3 and d=2

Sum of terms from 7th term to 12th term is (a+6d)+(a+7d)+(a+11d)=5a+51d=87

7 weeks

step-by-step explanation:

convert each fraction to the least common multiple of 20, so 3/4 = 15/20 & 1/10 = 2/20, then divide 15 by 2 and you get a little over 7, so the food will last 7 weeks.

452,489 to the nearest thousand is 452,000