I converting frm base ten to base 2 what do u do?​

See explanation for example.

Step-by-step explanation:

Say we want to convert 567 to binary aka base 2.

Look for highest power of 2 that will go into 567.

2^x will get us close to 567.

You could solve 2^x=567 in take the whole part of the number.

x=log_2 (567)=approximately 9.1

Of course you don't have to use logarithms here. You could have just found 2^0,2^1,...,2^9. You could have kept increasing the power on 2 until you exceeded the number,567, you wanted and use the power of 2 just before that number, 567.

2^9=512

So what's left 567-512=55

2^6=64 so that's too much, so 2^5=32 is what we will go with next.

55-32=23

2^4=16 and now 23-16=7 is left

2^2=4 so 7-4=3 is left

2^1=2 so 3-2=1 is left

2^0=1 and there is nothing left over

So we had 1, 2^9

No 2^8,2^7,2^6

We had 1, 2^5

We had 1, 2^4

We had no 2^3

We had 1, 2^2

We had 1, 2^1

We had 1, 2^0

The binary aka base 2 representation of 567 is 1000110111.

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90