Please help me solve this giys

(0, -2)

(-3, 1)

(3, -4)

Step-by-step explanation:

The constraints given as;

x + y ≥ -2

3x - y ≤ 2

x - y ≥ -4

Since we want to find vertices of the feasible region, we will ignore the less than or greater than sign and use the equal to sign to some simultaneously.

Let's add first and third constraint together to get;

2x = -6

x = -6/2

x = - 3

Put - 3 for x in equation 1 to get;

-3 + y = -2

y = 3 - 2

y = 1

Thus, vertex here is; (-3, 1)

Lets add first and third equations to get;

4x + 0 = 0

Thus, x = 0

Putting this for x in eq 1;

0 + y = -2

y = -2

vertex here is; (0, -2)

Lets subtract eq 3 from eq 2 to get;

2x = 6

x = 6/2

x = 3

Put 3 for x in eq 3;

x - y = -4

vertex here is; (3, -4)

answer: you have to send a photo of the question

step-by-step explanation:

i think the answer is b.

step-by-step explanation:

not 100% sure though.