SOMEONE HELP ME PLEASE Decide if the following scenario involves a permutation or combination. Then find the number of possibilities.

You are setting the combination on a five-digit lock. You want to use the numbers 12345 but you don't care what order they are in.

It's a combination, BUT...

Step-by-step explanation:

Definition: A combination is a grouping of outcomes in which the order does not matter. That's the difference between combination and permutation.

Combination Formula: nCr = (n!)/[r!(n-r)!)] where n stands for number of things and r the pair chosen

Applied to this case: We have n=5 (12345) and r=5 for the 5-digit lock combination.

5C5 = (5!)/[5!(5-5)] = 1

But Conceptually, this looks pretty much like a combination, but being the same range as number of items, we conclude that it's a permutation.

Permutation Formula: nPr = (n!)/(n-r)!

nPr = (5!)/(5-5)! = 120

Well, this looks way more accurate now, right?

Final The scenario involves a permutation, and there's 120 possible combinations of those 5 numbers in a 5-digit lock.

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it