HELPPP ASPA Classify the relations according to whether or not they are functions.
-3x = 15
2y = 10
3x − 0.25y = 3

{(2, 3), (1, 3), (5, 3), (2, 6)}
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an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

step-by-step explanation:

no solution.

b

step-by-step explanation: