Use the grouping method to factor the polynomial below completely 3x^3+9x^2+5x+15​

(x+3)( 3x^2 +5)

Step-by-step explanation:

3x^3+9x^2+5x+15​

Split into two groups

3x^3+9x^2     +5x+15​

Factor 3x^2 out of the  first group and 5 out of the second group

3x^2 ( x+3)  + 5(x+3)

Factor out x+3

(x+3)( 3x^2 +5)

(x+3)(3x²+5)

Step-by-step explanation:

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

4th option is correct xy=-10

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