Flying against the wind, an airplane travels 7760 kilometers in 8 hours. Flying with the wind, the same plane travels 3690 kilometers in 3 hours. What is the rate of the plane in still air and what is the rate of the wind

1100 and 130 (km/h)

Step-by-step explanation:

1. if the velocity of the wind is 'w' and the velocity of the plane in still air is 'p', then

2. it is possible to make up two equations:

the fly against the wind: (p-w)*8=7760;

the fly with the wind: (p+w)*3=3690.

3. if to solve the system made up, then:

4. the required rate of the plane in still air is p=1100 km/h; the rate of the wind is w=130 km/h.

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for