The probability that you will make the hockey team is 2/3 The probability that you will make the swimming team is 3/4.
If the probability that you make
both teams is 1/2
what is the probability that you at least make one of the teams?

p =

Step-by-step explanation:

Probability that you make the hockey team only: 2/3 * (1-3/4) = 1/6

Probability that you make the swimming team only: 3/4 * (1-2/3) = 1/4

Probability that you make the both team: 1/2

the probability that you at least make one of the teams: 1/6 + 1/4 + 1/2 = 11/12

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

image for option 4

step-by-step explanation:

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