The following house is called an A-frame house because it looks like the letter A from the front. Suppose that all edges of this A-frame house measure 6.5 yards, and the height of the house is 5.6 yards.

What is the area covered by the roof? [Type your answer as a number. Do not round.]

__ square yards

84.5 square yards roof

area of a square is A = a²

a = length of each side

The 2 triangular faces do not constitute "roof". The roof only covers 2 of the 3 square surfaces. Since we know the length of all edges is 6.5 yards:

A = (6.5)²

A = 42.25 yd²

This gives us the area of 1 of the 3 square sides. Since the roof covers 2 of the 3 sides (one is the floor/base), we must multiply times 2.

42.25 x 2 = 84.5

The height of the house would give you the area of the triangular faces, but since they are not considered "roof", you do not need to calculate their area.

show us the graphs dude

step-by-step explanation:

stops on an even number.