Find the equation of the line containing the points (5/7,4) and (-5/7,3)

y=

Step-by-step explanation:

Hi there!

We want to find the equation of the line containing the points (5/7,4) and (-5/7, 3)

The most common way to write an equation of the line is slope-intercept form, which is given as y=mx+b where m is the slope and b is the y intercept

So first, let's find the slope of the line

The formula for the slope calculated from two points is where (,) and (,) are points

We have everything needed to find the slope, but let's label the values of the points to avoid any confusion

=5/7

=4

=-5/7

=3

Now substitute into the formula

m=

m=

Subtract and simplify

m=

m=-1*

m=

m=

So the slope of the line is

Here is the equation of the line so far:

y=+b

We need to find b

As the equation of the line passes through both (5/7, 4) and (-5/7, 3), we can use either one of them to solve for b

Let's take (5/7, 4) for this case

Substitute x as 5/7 and y as 4

4=*+b

Multiply and simplify the fractions

4=+b

subtract 1/2 from both sides

=b

So the equation of the line is y=+

Hope this helps!

5+2x=a

asdasdsaadsaddsasds