A farmer has 1800 m of fencing. He needs to create two congruent rectangular fields, as shown.
Determine the maximum possible area of each field.

67,500 m²

Step-by-step explanation:

ASSUMING the fields look like this

                                                            |                    |                   |

                                                            |                    |                   | W

                                                            |||

                                                                                L                                                            

Let L be the length of the combined field and W be the width

2L + 3W = 1800

2L = 1800 - 3W

L = 900 - 1.5W

A = LW

A = (900 - 1.5W)W

A = 900W - 1.5W²

Area will be maximized when the derivative equals zero.

dA/dW = 900 - 3W

        0 = 900 - 3W

     3W = 900

       W = 300 m

L = 900 - 1.5(300)

L = 450 m

A = LW = 450(300) = 135,000 m²

so each sub field is 135000/2 = 67,500 m²

sup

step-by-step explanation:

the function makes a strait line horizontally with no x intercept but a y intercept at 9.