The restrictions for f(x)=2x+3/x^2−4 are ±2

True

False

 True

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Explanation:

If you meant to say , then we cannot have x^2-4 equal to 0

We can never have 0 in the denominator.

Set the expression equal to 0 and solve for x

x^2 - 4 = 0

(x-2)(x+2) = 0 .... difference of squares rule

x-2 = 0 or x+2 = 0

x = 2 or x = -2

So if either x = 2 or x = -2, then we have x^2-4 equal to zero.

So these are the values we must kick out of the domain to avoid a division by zero error.

In short, the restrictions for x are 2 and -2. That's why the statement is true.

the answer is the third / last answer

step-by-step explanation: