Hi~! can someone help me with this~? It costs 3 bowls and a jug 13.70, the jug costs $4.10 more that the bowl, how much does the jug cost-?

Thank u~!

$6.50

Step-by-step explanation:

Let the cost of a bowl and a jug be $b and $j respectively.

3b +j= 13.70 (1)

j= b +4.10 (2)

Substitute (2) into (1):

3b +b +4.10= 13.70

4b +4.10= 13.70 (simplify)

4b= 13.70 -4.10 (-4.10 on both sides)

4b= 9.60

b= 9.60 ÷4 (÷4 on both sides)

b= 2.40

Substitute b= 2.40 into (2):

j= 2.40 +4.10

j= 6.50

Thus, the jug costs $6.50.

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23