PLZ HELP!!

6 dogs

Step-by-step explanation:

To begin, we can start with that we know we want to work with two separate fractions. When we're doing this, we can make the denominators the same to make the comparisons easier.

Our two fractions are 1/8 and 3/4. To find a denominator that can work, we need to find the least common multiple. We can do this by listing the multiples of each number (in this case, the denominators) until one matches.

For 4, we have 4, 8, 12, 16, ...

For 8, we have 8, 16, 24, 32, ...

The lowest number in both of these is 8. Therefore, 8 is our least common multiple. Since 1/8 already has 8 as its denominator, we only need to change the denominator of 3/4.

To change the denominator, one way we can do this is to take (new denominator)/(old denominator) and multiply that value by both the numerator and denominator. We multiply that value by the numerator as well to ensure that the fraction stays the same.

We can then do (8/4) =2, so we multiply both 3 and 4 by 2 to get 6/8 = 3/4

Going back to our problem, we need to find how many dogs Dillon feeds with 6/8th of a can of food. Each dog takes 1/8th of a can of food every day, so we need to figure out how many times 1/8 goes into 6/8.

Because 1/8 is one-eighth of 8/8, or one whole, we can similarly say that 1/8 is one-sixth of 6/8, or six-eights. Therefore, Dillon has 6 dogs

10 * 563.67 = 5636.7

for b its (t) and c its (d)

step-by-step explanation: