Triangle XYZ was dilated by a scale factor of 2 to create triangle ACB and cos ∠X = 2 and 5 tenths over 5 and 59 hundredths. Triangles XYZ and ACB; angles Y and C both measure 90 degrees, angles A and X are congruent.

Part A: Use complete sentences to explain the special relationship between the trigonometric ratios of triangles XYZ and ACB

cosx=2.5/5.59

   "   =.4472

 "x"  =63.434°; so "a" is=.

When talking about triangles and a scale; the angles remain=. In this case; "a" and "x"; y=c; z=b.

The sides are 2x or x/2.

There's not enough imfo to give you measurements. You need at least: asa, sas or sss.

One formula is: a/sinα=b/sinβ=c/sinγ.

Step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

idk

step-by-step explanation: