A 1400-seat theater sells two types of tickets for a concert. Premium seats sell for $30 each and regular seats sell for $20 each. At one event $33,950 was collected in ticket sales with 10 seats left unsold. How many of each type of ticket was sold?

x = 638

y = 1190 - 638 = 552

Step-by-step explanation:

Let x = premium seats

let y = regular seats

x + y = 1190         (ten were not sold

30x + 20y = 30180    (amount collected

now multiply the first equation by 20 and subtract

20x + 20y = 23800

30x + 20y = 30180

-10x = -6380

x = 638

y = 1190 - 638 = 552

check it by multipying x and y by their price to see if you come up with the correct amount

Hope this helps

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

no this is a nonlinear negative