Mathematics, 16.07.2021 01:00 Fahaddie

A particular fruit's weights are normally distributed, with a mean of 344 grams and a standard deviation of 10 grams. If you pick 10 fruit at random, what is the probability that their mean weight will be between 334 grams and 354 grams

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Answer from: Kimmi4807

0.9984 = 99.84% probability that their mean weight will be between 334 grams and 354 grams.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 344 grams and a standard deviation of 10 grams.

This means that $\mu = 344, \sigma = 10$

Sample of 10:

This means that $n = 10, s = \frac{10}{\sqrt{10}}$

What is the probability that their mean weight will be between 334 grams and 354 grams?

This is the p-value of Z when X = 354 subtracted by the p-value of Z when X = 334.

X = 354

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{354 - 344}{\frac{10}{\sqrt{10}}}$

Z = 3.16

Z = 3.16 has a p-value of 0.9992.

X = 334

$Z = \frac{X - \mu}{s}$

$Z = \frac{334 - 344}{\frac{10}{\sqrt{10}}}$

Z = -3.16

Z = -3.16 has a p-value of 0.0008.

0.9992 - 0.0008 = 0.9984

0.9984 = 99.84% probability that their mean weight will be between 334 grams and 354 grams.

Answer from: Quest

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

Answer from: Quest

i think that you should ask google for the answer to that problem because if we don't know it google does

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A particular fruit's weights are normally distributed, with a mean of 344 grams and a standard devia...