The product of two consecutive terms of the Arithmetic sequence 5,8,11is 598.find the position of the term? ​

Step-by-step explanation:

Common difference is 3.

Let x be a term in the sequence. The next term in the sequence is x+3.

x(x+3) = 598

x² + 3x - 598 = 0

x = [-3 ± √(3²-4⋅1(-598))]/[2⋅1] = [-3 ± 49]/2 = 23, -26

-26 is an extraneous solution, so x = 23.

The two terms are 23 and 26.

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3