Three red balls, 5 green balls and a number of blue balls are put together in a sac. One ball is picked at random from the sac. If the probability of picking a red ball is 1|6, find the a) The number of blue balls in sac. B) the probability of picking a green ball. ​

a) 10 blue balls, b) 5/18

Step-by-step explanation:

a)

R=3, G=5, B=x (unknown)

probability of picking red = 1/6 and red = 3 so total = 3(6) = total is 18

3+5 = 8 so B=18-8 -> B=10

b) total is 18 and G=5 so green probability = 5/18

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%