The measure of two supplementary angles are A=(4a+7)° and B=(a-2)° find the measure of the two angles

147˚, 33˚

Step-by-step explanation:

supplementary angles means those angles add up to 180˚

so A+B = 180

substitute A and B with the values given.

(4a+7) + (a-2) = 180

combine like terms

5a + 5 = 180

5a = 175

a = 35

Now that we have a, substitute in the actual value of a into the expressions for each angle.

for <A: 4(35) + 7 = 147˚

for <B: 35 - 2 = 33˚

<A =147

<B =  33

Step-by-step explanation:

Supplementary angles add to 180

4a+7 + a-2 = 180

5a+5 = 180

5a+5-5 = 180-5

5a = 175

Divide by 5

5a/5 = 175/5

a = 35

<A = 4a+7 = 4*35 +7 = 140+7=147

<B = a-2 = 35-2 = 33

u rich

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.