Can someone help me with this math homework please!

Choice B

Quadrant II, because the slope is positive and the y intercept is negative.

===============================================================

Explanation:

The y intercept is -6 which places the graph below the x axis when x = 0. The graph will go uphill as we move to the right (since the slope is positive), so we cut through quadrant 4 and move to quadrant 1 at some point. Going in reverse of this, we go through quadrant 3.

Only quadrant 2 is never passed through or touched at all.

------------

Here's another way to see why this is. Notice that x < 0 is the case for quadrant 2 since we're to the left of the vertical y axis. If x is negative, then so is (2/3)x. Recall that negative times positive = negative.

Adding on -6 to any negative value just gets us in even more negative territory. So ultimately, y is always negative when x < 0.

But if x < 0 leads to y < 0, then we're in Q3 and not Q2. In short, x < 0 will never get us to Q2 no matter what negative x value we pick.

The graph below hopefully visually summarizes and confirms what we discussed so far.

i dont get the question

step-by-step explanation: