Find the equation of the line that passes through (-1,2) and is perpendicular to 2y=2x−1. Leave your answer in the form y=mx+c

y = x + 3

Step-by-step explanation:

given line in slope/intercept form:

y = x -1/2

slope of the perpendicular line = 1

equation of the line

y - 2 = x + 1

y = x + 3

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!