Vehicle A was parked alongside the right curb just behind vehicle B. The driver of vehicle A came out of the dry cleaner’s and hung the dry-cleaned clothes over the left rear window. The
driver entered vehicle A and checked for traffic in the rearview mirror. Seeing none, the driver
began to move the vehicle away from the curb and into the traffic lane. Vehicle C, traveling in
the same direction and coming from behind vehicle A, crashed into the driver’s side of vehicle
A. The impact pushed vehicle A into the left side of vehicle B.
How could the collision have been avoided?

26?

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.