(05.01 LC) Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity:
In the given triangle ABC, angle A is 90 degrees and segment AS is perpendicular to segment BC.

Which of these could be a step to prove that BC^2 = AB^2 + AC^2? (6 points)

A) By the cross product property, AB^2 = BC multiplied by BD.

B) By the cross product property, AC^2 = BC multiplied by BD.

C) By the cross product property, AC^2 = BC multiplied by AD.

D) By the cross product property, AB^2 = BC multiplied by AD.